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Mathematics 19 Online
OpenStudy (anonymous):

What is height of the pole?

OpenStudy (lgbasallote):

im going to predict this is a pytnagorean theorem problem

OpenStudy (anonymous):

Or a Trig prob

OpenStudy (anonymous):

OpenStudy (anonymous):

I so far

OpenStudy (anonymous):

Subtracted 100 from 64 to get 36 and I think its tangent.

OpenStudy (anonymous):

what tangent ? you don't have any angle

OpenStudy (anonymous):

90 degrees?

OpenStudy (anonymous):

DC = 36

OpenStudy (anonymous):

no, any other angle

OpenStudy (anonymous):

oh.

OpenStudy (anonymous):

its 36 i think !!

OpenStudy (anonymous):

choices ?

OpenStudy (anonymous):

36 is a choice but DC equals 36?

OpenStudy (anonymous):

Yup !!

OpenStudy (anonymous):

So DC = AD?

OpenStudy (anonymous):

wait a second

ganeshie8 (ganeshie8):

hint- \(\triangle BDA \textbf{ is similar to } \triangle ADC\) try setting up a proportion

OpenStudy (anonymous):

64 - 36 = 28?

OpenStudy (anonymous):

why subtract ?

ganeshie8 (ganeshie8):

nope you need to setup proportion

OpenStudy (anonymous):

Second nature.

OpenStudy (anonymous):

how?

ganeshie8 (ganeshie8):

is this q from similar triangles module ?

OpenStudy (anonymous):

No its a segment review.

OpenStudy (anonymous):

wait.. mastercat do you have any factor or multiple of 36 in Choices ??

ganeshie8 (ganeshie8):

hint 2 - \(\frac{BD}{AD} = \frac{DA}{DC}\)

OpenStudy (anonymous):

10 feet 8 feet 48 feet 36 feet

OpenStudy (anonymous):

I get 48 feet

OpenStudy (anonymous):

which seems logical from the drawing.

OpenStudy (anonymous):

How?

OpenStudy (anonymous):

I guess it does.

OpenStudy (anonymous):

Do you know how to set up the relation between the similar triangles?

OpenStudy (anonymous):

\[ \frac{x}{64}=\frac{36}{x} \]

OpenStudy (anonymous):

DA^2 = 64*36 DA = 8*6 = 48.. lol :P i was wrong

OpenStudy (anonymous):

Oh.

OpenStudy (anonymous):

Sometimes, although it can get visually complicated, it can help to draw the similar triangles "inside each other. You can do that by flipping the triangle ADC by 90° counterclockwise

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