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pls find the equation of the parabola in standard form and identify the vertex, focus and directrix :) y^2 + 25 = 6x -1
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y^2=6x-26 y^2=6(x-(26/6)) y^2=6(x-(13/3)) \[(y-0)^{2}=4(6/4)(x-13/3)\]
what if it there was a y already ? like it's gonna be y^2 + 20y = 6x -1
y^2+20y+100-100=6x-1 (y+10)^2=6x-1+100 (y+10)^2=6x+99 (y+10)^2=6(x+(99/6)) (y+10)^2=6(x+33/2)
or for standard form:::: (y+10)^2=4(6/4)(x+33/2)
i used completing the square method out here.......
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thank you so much ! :)
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