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If f(x)=5x-3 then what is f^1(x)?
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Do you mean \(f^{-1}(x)\)?
You first multiply 5 to a number, then you subtract 3. You'd do the exactly opposite thing. You first add 3, then you divide 3 from the whole.
There's a technical way to do that too.
\( \color{Black}{\Rightarrow f(x) = 5x - 3 \Longrightarrow y = 5x - 3}\) \( \color{Black}{\Rightarrow y + 3 = 5x}\) \( \color{Black}{\Rightarrow \Large {y + 3 \over 5} \normalsize = x}\)
As you have solved for \(x \) in terms of \(y\), you may now replace \(x\) with \(f^{-1}(x)\) and \(y \) with \(x\).
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That gets you \[ f^{-1}(x) = {x + 3 \over 5}\]
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