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OpenStudy (anonymous):
2ln 3x +1 = 5
Could you find the solution to this please?
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OpenStudy (anonymous):
Please help!
OpenStudy (anonymous):
Subtract 1 both the sides..
OpenStudy (anonymous):
ok.. then what
OpenStudy (anonymous):
then divide by 2 both the sides..
OpenStudy (anonymous):
alrighty then?
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OpenStudy (anonymous):
show me your work...
OpenStudy (anonymous):
ln3x=2?
OpenStudy (anonymous):
Yes you are right...
OpenStudy (anonymous):
good, now what?
OpenStudy (anonymous):
Take antilog both the sides:
\[3x = Antilog(2)\]
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OpenStudy (anonymous):
is the answer 7?
OpenStudy (anonymous):
sorry i meant 4
OpenStudy (anonymous):
What is antilog (2) i don't know..
OpenStudy (anonymous):
I dont know myself
OpenStudy (anonymous):
\[Antilog(2) = 7.39\]
Divide it by 3 and you wll get x..
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OpenStudy (anonymous):
What are the options ??
OpenStudy (anonymous):
2.46
OpenStudy (anonymous):
Yes I got the same ..
OpenStudy (anonymous):
Thank You so much, I'm almost done... log 3 5 + log 3 x = log 3 10 can you help me with this one?
OpenStudy (anonymous):
Use:
\[\log(a) + \log(b) = \log(ab)\]
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OpenStudy (anonymous):
\[\large \log_3(5x) = \log_3(10)\]
Now logs are same so the terms inside will be equal:
\[5x = 10\]
find x from here..
OpenStudy (anonymous):
Nice now can you just check this one for me? 22n = 16-, i said the solution is -2
OpenStudy (anonymous):
22n = 16 ??
OpenStudy (anonymous):
22n = 16^-1 ....sorry
OpenStudy (anonymous):
no sorry again its 2^2n=16^-1
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OpenStudy (anonymous):
\[\large 2^{2n} = 16^{-1} \implies 2^{2n} = 2^{-4}\]
\[2n = -4\]
\(n = -2\)
OpenStudy (anonymous):
Yes you are right..
OpenStudy (anonymous):
Thank you sooo much :)
OpenStudy (anonymous):
Welcome dear..
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