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sin^2 theta = 4-2cos^2theta Solve.
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\[sin^2\theta = 1-\cos^2\theta \] use this as a substitution for the left hand side of this equation, then you will obtain an easier equation.
yeah I got that far, then what….
\[cos^2\theta=3 \] \[cos \theta = \sqrt{3}\] you could take the inverse function of that, but we know already that there is no solution for that because it's only defined between values of -1 and 1
OKAY Thank youuuu
you're welcome
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