Question

How do you solve this with logs?
2^2x + 2^x - 12 = 0

Answer 1

\[2^{2x} + 2^{x} - 12 = 0\]

Answer 2

use properties of exponents

Answer 3

\[Let\ Y = 2^x \ then:\]
\[Y^2+Y-12=0\]

Answer 4

Just remember that Y cannot be negative.

Answer 5

Where did Y come from?

Answer 6

I picked a letter. The point is that this is the same form as any old quadratic equation.

Answer 7

maybe you'll get it when you see the answer

Answer 8

Can you solve for Y?