Question

i have a problems with my algebra homework

Answer 1

Okay, post it here :)

Answer 2

okay.
now post your problem here.

Answer 3

take you time baby, relax ;)

Answer 4

It's Yao Ming!

Answer 5

it is 4x to the 4th power - 7x to the 3rd power - 12x to the 4th power +6x to the 3rd power

Answer 6

\(4x^4-7x^3-12x^4+6x^3\)?

Answer 7

yes

Answer 8

what you ned to do is combine like terms. Let me rewrite it a little for you
\(4x^4-12x^4-7x^3+6x^3\)

Answer 9

@zscdragon , please read the code of conduct.
http://openstudy.com/code-of-conduct
We are here to help people, not give them the answers...

Answer 10

By the way, my post lagged, so somehow it came out after @zscdragon 's did. But, essentially, we did the same thing.

Answer 11

Actually because my internet is being slow. And I was serious about giving the answers. We are here to teach, not to cheat.

Answer 12

More importantly, @tanyahosler , do you understand?

Answer 13

I mean the problem xD

Answer 14

what about helping me with this one -5a to the 2nd power; a=-2 can someone help me thru this one

Answer 15

yeah i got it i understand how they got it

Answer 16

replace the a with a negative 2

Answer 17

Right now you have
\(-5a^2\), put in a -2 (with parenthesis!) inside, and tell me what you get

Answer 18

3

Answer 19

Did you read
http://openstudy.com/code-of-conduct
@zscdragon ?
We are not supposed to nor allowed to just give answers like that.

Answer 20

3 squared

Answer 21

@tanyahosler , how did you get that answer?

Answer 22

subtracted it

Answer 23

was i right

Answer 24

No :( Uh, let me show you what I meant

Answer 25

ok

Answer 26

So, we have \(-5a^2\)
instead of \(a\), we want (-2). So just put it in.
\(-5*(-2)^2\)
Exponents first
Can you try to do the rest?

Answer 27

so 10squared

Answer 28

No - square what's inside the parenthesis

Answer 29

ok i'm lost

Answer 30

Exponents are before multiplcation and division, always!

Answer 31

i'm lost

Answer 32

@tanyahosler look relax, everything's fine, just look at what I'll say

Answer 33

Here, should look like this
\(-5*(\text{ }(-2)^2\text{ })\)

Answer 34

\[-5 * a^2\] is the equation, now what if you replace 'a' by -2

Answer 35

@zscdragon , Please do not curse on this site. I'm reporting you for foul language.

Answer 36

i am still a lil confused

Answer 37

tanya, you want to "square" the a. The a is -2 in this case . What's negative 2 squared?

Answer 38

@tanyahosler , ok don't listen to that @inkyvoyd, he's all confused and doesn't know his material

Answer 39

please guys i need help i have to have this in by saturday

Answer 40

@tanyahosler , It's okay. I'll help you by personal message, because zsc is being distracting. Why don't you tell me what you don't understand in a message :)

Answer 41

ok

Answer 42

it isn't a test it is homework and i don't know how to put the problems in here right

Answer 43

It's alright, I'll spend time to explain it. I have a few hours on hand, and I'm willing to use them :)

Answer 44

ok i'm not sure how to do algebra anymore been 22 yrs since school

Answer 45

the next one is going to be really difficult for me to put in cause i don't know how

Answer 46

Press the equation button. It should help.

Answer 47

Other wise you could try taking a screenshot, and uploading it.

Answer 48

ok it is in my textbook

Answer 49

but i wanna get this one done

Answer 50

Hm. Try using the equation button. Tell me if you have trouble.

Answer 51

i don't know how to enter it in there

Answer 52

I see that you have gone from insulting language to stalking. I am slightly annoyed, but more so amused. I do request that if you want to publicly "embarrass" me, that you DO NOT POST HERE AND HIJACK SOMEONE'S THREAD. Please post it in chat. Thank you.

Answer 53

O_O!!!!!!!!!!!!!!!!!

Answer 54

I'm going to completely ignore you, not because I don't want to answer, but because this isn't your thread to hijack (nor is it mine). If you have a problem with me, let's fight it out in chat, instead of hijacking tanya's post.

Answer 55

\[\sqrt{b ^{2-4ac;b=3,a=-1,c=-2}}\]

Answer 56

not sure if i did that right

Answer 57

Can You Like Build A Bridge And Get Over It?

Answer 58

Oh, I know what you are trying to post. Is it
\(\sqrt{b^2-4ac};b=3,a=-1,c=-2\)

Answer 59

@Zscdragon Stop trolling or I will report you

Answer 60

@Mayah3 , My side's open, but I don't think his is. :(

Answer 61

@Carniel everything I said is based on reason, please re-read that a few times

Answer 62

yes that is it inkyvoyd

Answer 63

Okay @tanyahosler . Put in what you are given for the letters.
\(\sqrt{b^2-4ac}\) a=-1, b=-2, and c=3

Answer 64

@zscdragon , Please don't use this thread to insult me. Please insult me in chat. You are being incredibly rude and disruptive to the OP.

Answer 65

Again your getting out of hand.

Answer 66

b = 3, a=-1, c= -2

Answer 67

a=-1, b=-2, and c=3
Put (-1) for all the a's you see. Like this.
\(\sqrt{b^2-4(-1)c}\)
That make sense to you?

Answer 68

@inkyvoyd i never insulted you. all i write are facts and truths, nothing less, nothing more. u dont like it, dont read it ;)

Answer 69

yes

Answer 70

Now, try the same for b.

Answer 71

\(\sqrt{b^2-4(-1)c}\)
b=-2 here. Remember, just put the negative 2 in parenthesis, and square it. ignore the square root for now, and just type in what you get without the square root. Try using "Draw" if you have to.

Answer 72

9

Answer 73

can he just shut up?

Answer 74

@zscdragon , I'd be happy to answer any of your comments if you post them in the appropriate math chat. What you are discussing does not pertain to what Tanya is trying to learn about, and thus is going to be ignored completely by me. Again, post it in chat, and I will answer. This is the last time I will reply to you on this thread because you are not being productive. Thank you.

Answer 75

Your posting in a OQ he is trying to answer. Anything else out of you and I will report you