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how do i change y+3=6/5 x + 12/5 to a general linear form?
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\( \color{Black}{\Rightarrow y + 3 = \Large {6x \over 5} + {12 \over 5}}\) Since the denominators are equal, you may add both the numerators. Okay?
Are you there? @dorkkk
yes
So did you get my point right there? :)
so y+3=18/5x
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No! \(6x + 12\) remains as it is.
?
\( \color{Black}{\Rightarrow y + 3 = \Large{6x + 12 \over 5} }\) Do you get it till this point?
yes
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