(Using the quadratic formula) What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth?

Question

parthkohli · Answer

$ \color{Black}{\Rightarrow 4x^2 + 12x + 3 = 0 }$ is your quadratic equation, okay?

parthkohli · Answer

$$ \color{Black}{\Rightarrow x = {-b \pm {\sqrt{b^2 - 4ac} } \over 2a} }$$

parthkohli · Answer

Get it?

anonymous · Answer

https://www.wolframalpha.com/

parthkohli · Answer

So, $$x  = {-12\pm \sqrt{12^2 - 4(4)(3)} \over 2(4)} $$

mathslover · Answer

$$\large{ax^2+bx+c=0}$$ 
$$\large{\alpha ,\beta  = \frac{-b\pm \sqrt{b^2-4ac}}{2a}}$$ 
$$\large{\textbf{alpha and beta r the roots of the equation}}$$

parthkohli · Answer

Nuh!

$$\alpha = {-b + \sqrt{b^2 - 4ac} \over 2a}$$$$\beta = {-b - \sqrt{b^2 - 4ac} \over 2a} $$

anonymous · Answer

okay

mathslover · Answer

firstly i will prefer you to rearrange the given equation in the form of standard form of a quadratic equation : 

$$\large{4x^2+3-12x=0}$$ 
$$\large{4x^2-12x+3=0}$$ 
Compare the second one with $\large{ax^2+bx+c=0}$ 

Can you tell me that what is a , b and c ?

mathslover · Answer

@simplybeyoutiful ?

mathslover · Answer

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