Help? I don't know what I'm doing wrong... Use the table for sine values, and find x to the nearest tenth. (My Answer) x (Approximately) = ? 1.0
sin(48)=10/x
Is this what you did?
oh wait, i think i may know now, heres my work sin 48* = x/10 sin 48* = 0.7431 0.7431 = x/10 x = 10(0.7431) 0.1
No, what is sin?
sin is opposite over hypotenuse and could one of you help me with my question please
i could try sry i was away from the computor when u asked what sin was
i hav instructions for the lesson and the definition they gave me for Sine ratio was: with respect to an acute angle of a right triangle, the ratio formed by the side opposite the acute angle over the hypotenuse.
i looked over ur problem and i dont really understand what to do on that either sorry :(
Okay, sin is opposite over hypotenuse. Sin 48= opposite/ hypotenuse. What's the opposite of sin 48?
10 right?
Yup!
This is your mistake.
so that would be sin 48* = 10/x
Exactly :)
okay so the problem would be: sin 48* = 10/x sin 48* = 0.7431 0.7431 = 10/x 10 = x(0.7431) and then i divide?
Yes
k i got 0.07431 so that goes to 0.1 when rounded right?
How did you get that? O.o!
i divided 0.07431 by 10 and i got 0.07431 and i rounded to the nearest tenth and since 7 is a high number i rounded it to 0.1
yepp :D
awesome lol
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