explain how to factor trinomial forms x^2 + bc +c and ax^2 + bx + c

Question

happinessbreaksbones · Answer

hmm well I'm still new to this and I hope my answer is right.. but I believe it would be factored as:
$$x ^{2} +bc + c$$
example equation: $$2x^2 - 2x - 24$$
the answer would be $$2(x - 4)(x + 3)$$
because you have to distribute as well as FOIL.. x • x = x^2 and 2 • x^2 = 2x^2
-4 • 3 = -12 and 2 • -12 would be -24 and as for -2x in the middle..
continue to FOIL -4 • x = -4x and -4x + 3 = -1x.. -1x • 2 (on the outside) = -2x..
so $$2x^2 - 2x - 24$$ would equal $$2(x - 4)(x + 3)$$ 

I really hope this helped. Hopefully if not, someone else can help or I can further explain?