Question

WHAT IS THE PRODUCT OF:

Answer 1

@Calcmathlete

Answer 2

@lgbasallote

Answer 3

Try cross canceling.
\[\frac{2t^3}{4t + 8} \times \frac{t + 2}{8t} \implies \frac{2t^3}{4(t + 2)} \times \frac{t + 2}{8t} \implies \frac{\cancel{2}t\cancel{^3}^2}{\cancel{4}2\cancel{(t + 2)}} \times \frac{\cancel{t + 2}}{8\cancel{t}} \implies ?\]

Answer 4

@Calcmathlete so everything cancels out? so whats my answer?

Answer 5

Just take out the stuff that cancels. What do you think?

Answer 6

t over 16?

Answer 7

t squared over 16?

Answer 8

Yup. The second one. \(\frac{t^2}{16}\)