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Calculate the weight of CO having the same no,of oxygen atoms as are present in 22g of CO2
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Alright, I'm a little rusty on chem since school's out, so you're going to have to check what I did to make sure it's right. The first will be the stoich and the second will be an explaination as to how I got that part. (22g CO2)*(1 mol CO2/44.0095g CO2)*(2 mol O/1 mol CO2)*(1 mol CO/1 mol O)*(28.0101g CO/1 mol CO)= 28g CO (Given amount) * (molar mass of given amount) * (# mol of O in 1 mol of CO2) * (# of O in 1 mol CO) * (molar mass of CO) = Answer
28g
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