Question

(1/x)-(4/3x)=(1/x-2) need to solve equation

Answer 1

\[\Large \frac 1x - \frac{4}{3x} = \frac{1}{x-2}\]
is this the question?

Answer 2

nope

Answer 3

\[\Large \frac 1x - \frac{4}{3x} = \frac 1x - 2\]

Answer 4

yes it is soory

Answer 5

sorry

Answer 6

lol you confuse me

Answer 7

so it's the first one?

Answer 8

well the last part is (1/x-2)

Answer 9

the x-2 is the denominator

Answer 10

so is it first one or second one?

Answer 11

1

Answer 12

first

Answer 13

start by converting the left side to common denominators
\[\frac 1x = \frac{3}{3x}\]
therefore i will turn the equation inot
\[\frac{3}{3x} - \frac{4}{3x} = \frac{1}{x-2}\]
\[\frac{3-4}{3x} = \frac{1}{x-2}\]
\[\frac{-1}{3x} = \frac{1}{x-2}\]
cross multiply
\[-(x-2) = 3x\]
\[-x + 2 = 3x\]
add x to both sides
\[2 = 3x +x\]
\[2 = 4x\]
can you solve for x now?

Answer 14

yes

Answer 15

great