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Mathematics 21 Online
OpenStudy (anonymous):

Factorise: 2u^4-4u^2+2u^2-4 .

OpenStudy (lgbasallote):

step 1: group them \[(2u^4 - 4u^2) + (2u^2 - 4)\] step2: factor out common factors \[2u^2 (u^2 - 2) + 2(u^2 - 2)\] step 3: factor out again \[(u^2 - 2)(2u^2 + 2)\] does that help?

OpenStudy (anonymous):

yes! :D thank you agaaaiiin

OpenStudy (lgbasallote):

actually...if you look at the second factor..you can factor something out again...can you find it? ;)

OpenStudy (anonymous):

the 2 ?

OpenStudy (lgbasallote):

right! so what do you think will it look like?

OpenStudy (anonymous):

2(u^2+1)(u^2-2)?

OpenStudy (lgbasallote):

right. that is now the fully factored form

OpenStudy (anonymous):

I seee ;D thanksss x

OpenStudy (lgbasallote):

welcome welcome :D

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