Question

Circle P has a radius of 8 units with center P at (-2, 1). Which equation defines circle P?

Answer 1

(x + 2)2 + (y – 1)2 = 8

(x – 2)2 + (y + 1)2 = 8

(x + 2)2 + (y – 1)2 = 64

(x – 2)2 + (y + 1)2 = 64

Answer 2

the standard equation of a circle with center (h, k) and radius r is given as:
\[\huge (x-h)^2+(y-k)^2=r^2 \]
which one of those choices will fit this equation?

Answer 3

idk ?
im not sure how to do this D:

Answer 4

what's the (h, k) , the center, in your problem? give me the coordinates...

Answer 5

-2 & 1

Answer 6

so h=-2, k=1..
can you plug that into the equation i gave u?

Answer 7

(x-2)^2 + ( y-1)^2=8^2 ?

Answer 8

but i thought you said h=-2,, so shouldn't it start as (x - -2)^2 ?

Answer 9

oops, i thought i hit the - button twice.
but yes it should be (x--2)^2

Answer 10

ok... without giving me the choices, just replace the given values into the equation i gave....

Answer 11

after simplifying it, which is the correct answer?

Answer 12

(x + 2)2 + (y – 1)2 = 64 ?

Answer 13

that's the one....:)

Answer 14

okay ' now it makes sense.
can you explain how to find the center and radius of this circle?
please .

Answer 15

from a graph

Answer 16

ok... close shop here and post it as another question....:)

Answer 17

okay'

Answer 18

ok...:)