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What is the equation of the line in standard form that passes through the point (–2, –3) and is parallel to the line y = x + 9?
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slope of \(y=mx+b\) is \(m\) in your case \(m=1\) so your slope should be 1
okayy , where do i go from there ?
then use the point slope formula \(y-y_1=m(x-x_1)\) with \(x_1=-2, y_1=-3.m=1\)
you should start with \[y+3=1(x+2)\] then get rid of the silly "1" and write \[y+3=x+2\]
and finally you can solve for \(y\) by subtracting 3 from both sides and write \[y=x-1\]
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so then this would be my final equation ?
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