Question

please help asap

Answer 1

\[x^2+8x=-13\]\[x^2+8x+13=0\]
\[ax^2+bx+c=0\]\[x=\frac{-b\pm\sqrt{b^2-4a}}{2a}\]

Answer 2

i dont understand

Answer 3

a,b,and c are the coefficients of your terms

Answer 4

ok

Answer 5

so if you look at your equation you have

a=1,b=8, c=13 now use the quadratic formula he posted

Answer 6

i tried :( i suck at this

Answer 7

\[\frac{-13\pm\sqrt{64-4(1)(13)}}{2}\]

Answer 8

i got A ?