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Mathematics 17 Online
OpenStudy (anonymous):

What is the equation of the parabola in vertex form? 0=y^2-x+2y-3

OpenStudy (anonymous):

OpenStudy (anonymous):

complete the square for y y^2 + 2y + 1 = (y + 1)^2 Can you do the rest?

OpenStudy (anonymous):

so 0 = (y + 1)^2 - x - 4 and then..

OpenStudy (anonymous):

why -4?

OpenStudy (anonymous):

Because we added an extra minus 1 to complete the square so we need to subtract it to keep the equality

OpenStudy (anonymous):

sorry plus one

OpenStudy (anonymous):

oh ok so then it would be C because -x-4 are left right?

OpenStudy (anonymous):

The last step is to move -x -4 to the left hand side. What is C?

OpenStudy (anonymous):

C is (x+4)=(y+1)^2 i posted the options as a pic sorry

OpenStudy (anonymous):

Yep, sounds good. Find a couple x,y pairs with the new equation and see if they solve what you were given originally, just to check your work.

OpenStudy (anonymous):

cool thanks!

OpenStudy (anonymous):

yw

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