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Find the area of a 120° sector of a circle whose radius is 6.
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Area of a full circle A = pi*r^2
Area of a sector of a circle A = (angle/360)*(Area of full circle) A = (angle/360)*pi*r^2
answer has to be in pi
339.12
A = (angle/360)*pi*r^2 A = (120/360)*pi*6^2 Remember to leave the 'pi' alone (and don't replace it with 3.14...)
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so it would be 3 x 36 = 108
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120/360 isn't 3 though
you divided in the wrong order
.33
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.33 x 36 11.88
it's more like 0.333333 where the 3's repeat forever
or just 1/3
(1/3)*(36) = 36/3 = 12 So the answer is 12pi
so the answer is 12
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thanks for helping
12pi, but yes you pretty much have it
yw
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