what is the smallest number of portriats that can be distributed equally among either four grandparents and six aunts and uncles with no portraits left over?
you need to find the common denominator of 6 and 4
if you had this problem \[\frac{1}{4}+\frac{1}{6}\] what would you do
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i guess add it 2 over ten .or 2over five not sure dont understand
i guess its 2
the common denominator
not quite the common denominator is going to be a number of a factor or 4 or 6 so go through each factor 1*4=4 2*4=8 3*4=12 4*4=16 now do 6 1*6=6 2*6=12 3*6=18 you can see that both have 12, therefore 12 is your common denominator in which 4 and 6 go evenly into
so your answer is 12 if you do this the long way you can see.. first you need 6 pictures because the second part of the problem distributes them to 6 people for 6, it is evenly distributed for 6 but you're left over with 2 for 4 people for 7, you have 3 leftover for 4 people and 1 leftover for 6 people for 8, you have none leftover for 4 people but 2 leftover for 6 people for 9, you have 1 leftover for 4 people, and 3 for 6 people for 10, you have 2 leftover for 4 people and 4 for 6 people for 11, you have 3 leftover for 4 people and 5 leftover for 6 people 12 you give 3 pictures to the each person for the 4 people and 2 to each for the 6 peopl
thanks alot ive never been good at math at all thanks bunches
Look at the pattern shown below. What number is missing from the pattern? 20, 22, 26, 34, __,8
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