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OpenStudy (anonymous):
true or false If P and Q are two points in the plane, the perpendicular bisector of PQ is the set of all points equidistant from P and Q.
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OpenStudy (anonymous):
True
OpenStudy (anonymous):
are you sure?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
can you explain to me why tho?
OpenStudy (anonymous):
well do you know how to construct a pb?
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OpenStudy (anonymous):
like with a compass & straigtedge?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
ooooooooooh i see.
OpenStudy (anonymous):
shpanks.
OpenStudy (anonymous):
exactly. since you do it with any arbitrarily sized circles, it is equidistant for any radius.
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