Which equation does not represent a function? A) y = 2x + 3 B) x = 4y + 7 C) x2 = -2y + 1 D) y2 = -5x - 8
The one in which two different y values give the same x value.
so we have to put it in slope intercept form to get the y value? I'm so confused
The given equations are not all lines so they cannot all be put in slope-intercept form.
so what form do I put it in?
Solve for y..
C?
its either c or D
wait..... What values do we substitute for y?
You could resort to just looking at the equations and thinking something like this: For the first equation, y = 2x+3, replace y with 1 and you get -1 for x. Replace y with -1 and you get -2 for x. Different y, different x.
Now try that with the last equation, y^2=-5x-8. Replace y with 1 and you get -9/5 for x Replace y with -1 and you get -9/5 for x That cannot be a function because now you have two ordered pairs with the same first number.
One more hint.. A function must produce a unique y value for each x. But when we take square root, there are two possible (real) roots + or - of the value.
so it's d because the 2 y values equal the same x value?
Exactly.
ohhhhh ok thanks guys :)
yw
i have to take my eoc next week and i have a bunch of practice stuff to do
Keep working hard and you'll be fine.
:)
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