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square root 4x+1 -5=2 solve the equation???
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square on both sides
\( \color{Black}{\Rightarrow\sqrt{4x - 1} = 2 + 5 }\) \( \color{Black}{\Rightarrow \sqrt{4x - 1} = 7 \Longrightarrow (\sqrt{4x - 1}})^2 = 7^2\)
\[\sqrt{4x+1} - 5 = 2\] add 5 to both sides \[\sqrt{4x + 1} = 7\] square both sides \[4x + 1 = 49\] subtract 1 from both sides \[4x = 48\] divide both sides by 4 \[x = \frac{48}{4}\] got it?
So, \(4x - 1 = 49\). Get it till this point?
I got it...thank you
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welcome :D
i am assuming you would simplify??? so your answe is 12???
Yes.
thank you
You're welcome :)
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