Question

2 over 6 - radical 3

Answer 1

\[\frac{2}{6-\sqrt 3}\]
multiply by conjugate
\[\frac{2}{6-\sqrt 3} \times \frac{6+\sqrt 3}{6+\sqrt 3} \implies \frac{2(6+\sqrt 3)}{(6 + \sqrt 3)(6 - \sqrt 3)} \implies \frac{12 + 2\sqrt 3}{6^2 - (\sqrt 3)^2} \implies \frac{12 + 2\sqrt 3}{36 - 3}\]
do you get it? or do you need more help?

Answer 2

I Understand Thank You Soo Much ^.^

Answer 3

myy pleasure :D