Question

For the system shown below, what are the coordinates of the solution that lies in quadrant I?

3y^2-5x^2=7
3y^2-x^2=23

Answer 1

(-2,3)??

Answer 2

or (2,3)?

Answer 3

Hint:

1.) Isolate 3y^2:

3y^2 = 7 + 5x^2
3y^2 = 23 + x^2

2.) Set 3y^2 = 3y^2

7 + 5x^2 = 23 + x^2

3.) Finish the rest

Answer 4

I thought that there are 4 solutions, one in each quadrant: (± 2, ± 3)

Q I : (2, 3)
Q II : (−2, 3)
Q III : (−2, −3)
Q IV : (2, −3)

Answer 5

Yeah, you're right. Four solutions

Answer 6

so (2,3) is my answer?

Answer 7

You have four solutions, not one.

Answer 8

Oh, yeah, for quadrant 1, (2,3)

Answer 9

Cool thanks soo much :)