Question

Use the method of substitution to solve the system of linear equations.
3a=7-b
3a=6-b

Answer 1

Hmm...that system does not seem possible. If 3a=7-b, then 3a cannot = 6-b.
Proof:
Let's make b the subject of the first equation:
b=7-3a
Then substitute it in the second equation:
3a=6-(7-3a)
3a=6-7+3a
0=-1

Answer 2

Or another way to think about it, since 3a=7-b, and 3a=6-b,
then that means 7-b=6-b. There is no value for b that will make this true.

Answer 3

So there will be no solutions since 0=-1 is not true

Answer 4

Yes :)