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Solve 2(x-1)(x-8)=0 PlEaSe HELP? :)
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if (something) times (something else) is zero, then one of those must be zero
Hint: 2(x-1)(x-8)=0 x-1=0 or x-8=0 By using the zero product property
agreed?
Agreed^
so, in your case, we have:\[2(x-1)(x-8)=0\]which means either: 2 = 0, or x - 1 = 0, or x - 8 = 0
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now obviously 2 cannot equal zero, so we can eliminate that
x=1,x=8?
which leave us with: x - 1 = 0, or x - 8 = 0
correct!
Thanks!
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yw :)
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