Question

The sum of three consecutive integers is 267. What is the largest integer?

Answer 1

\(x + x + 1 + x + 2 = 267\)
Solve for x + 2

Answer 2

how would i solve it? im not good at intgers

Answer 3

let x be the first integer
x + 1 second integer
x+2 third integer

sum of the three is 267 so

x + x + 1 + x+ 2 = 267
3x + 3 = 267
3x = 267 - 3
3x = 264
x = 88
x + 1 = 89
x + 2 = 90

Answer 4

Basically, three consecutive numbers can be represented by a number, a number more than that, and a number more than the second number.

Answer 5

so is the answer 2?

Answer 6

Solve the equation for x and then add two to x.

Answer 7

im still confused...

Answer 8

3x=264

Answer 9

x + x +x = 267 - 2 - 1

Answer 10

thilet us consider that digit is x then sum of three digits will
x+x+1+x+2=267
3x+3=267
3x=267-3
3x=264
x=88 this is 1st digit
2nd digit was x+1 so
88+1=89

3rd was x+2 so
88+2=90 largest is 90...

Answer 11

but it is consecutive integers . so its x+0 , x+1, x+2