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Inverse of this function \[y=x^3-6x^2+12x \] one medal will be given to correct answer
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by "inverse" do you mean something like f^-1 (x)?
yeah...
(x-8)^1/3 + 2
can by written as \[\Large y=(x-2)^3+8\]
now \[\Large y-8=(x-2)^3\]
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replace each x with y and each y with x
\[\Large x-8=(y-2)^3\]
and replace it with f^-1(x)
sorry typo!
\[\Large (x-2)^{1/3}+2=f^{-1}(x)\]
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\[f^{-1}(x)=\sqrt[3]{x-8}+2 \]
u made a little mistake ..........:D
yes i did it again !
m quite notorious for typo mistakes :P
lol.....:)
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\[\Large \sqrt[3]{x-8}+2=f^{-1}(x)\] just wanted to correct it ! :)
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