Question

a) Write the next three terms and the twelfth term: 3, 12, 48…
b) Describe the rule.

Answer 1

Seems like we are multiplying 4 again and again, so this is a G.P.

Answer 2

\(T_n = T_1 \times r^{n - 1} \Longrightarrow T_n = 3 \times 4^{n - 1}\)

Answer 3

Now, you substitute n with 4,5,6 and 12.

Answer 4

For 12th term use:

\[\large a_{12} = (a) \cdot (r)^{n-1}\]

Here a = 3, n = 12 and r = 4
Now find the 12th term..

Answer 5

@waterineyes \(A_n\)*

Answer 6

I told you you can write any symbol there..

Answer 7

thanks guys

Answer 8

You're welcome :)

Answer 9

it does work but can u pls tell me how u work out the formula?