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OpenStudy (anonymous):
If (x^2 + ax - 10) ÷ (x + 2) = (x - 5), then a =
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OpenStudy (anonymous):
A. -7
B. -3
C. 7
D. 3
Parth (parthkohli):
Then, \(x^2 + ax - 10 = (x - 5)( x+ 2)\)
Do you get it till here?
OpenStudy (anonymous):
kinda.....
Parth (parthkohli):
Yeah. I just multiplied both sides by \(x + 2\).
OpenStudy (anonymous):
oh ok
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OpenStudy (anonymous):
yeah i get it
Parth (parthkohli):
Great! Can you simplify \((x - 5)(x + 2)\)?
OpenStudy (anonymous):
Middle term will be negative because here the factors are -5 and 2..
So "a" will be negative..
OpenStudy (anonymous):
@ParthKohli do you mean setting them equal to 0?
OpenStudy (anonymous):
So your answer can be either A or B..
You have to check now the sum:
-5 + 2 = ??
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Parth (parthkohli):
Nope.
\(x^2 + a x - 10 = (x + 5)( x - 2)\)
You have to simplify the right hand side by multiplying x + 5 and x - 2.
OpenStudy (anonymous):
oh ok so its x^2+3x-10?
OpenStudy (anonymous):
@ParthKohli are you there?
Parth (parthkohli):
Yep :)
Parth (parthkohli):
Sorry for the late reply, I was eating my dinner.
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Parth (parthkohli):
\( \color{Black}{\Rightarrow (x + 5)(x - 2) = x(x - 2) + 5(x - 2) = x^2 - 2x + 5x - 10 = x^2 + 3 x - 10 }\)
Parth (parthkohli):
So what is \(a\)?
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