@waterineyes
can you please explain how to solve this. Anyway got 100% in my exam last Saturday!
-3, because it will divide by zer
I dont understand why x+3 will be 0 here why not x+4?
I dont understand why x+3 will be 0 here why not x+4?@AugustinusSextus
for what value of x \[\frac{x+4}{x+3}\] suppose you put -4 then it would be \[\frac{0}{-1}=0\] but suppose you put -3 \[\frac{1}{0}=\text{ undefined }\]
I am so sorry @waterineyes
What is the question can you explain it here..
Yeah as I can't see it, it is undefined.. Ha ha ha..
For what value(s) is the statement x+4 undifined? x+3
Idont really know how to use drawing here though
When a fraction gets undefined?/ When its denominator becomes 0.. So: x + 3 = 0 (this condition we have to avoid) So \(x \ne -3\)..
It's a theory, remember it , you put all the time The denominator \[\neq 0\] In this case: \[x +3 \neq 0\] \[x \neq -3\]
How about when the numerator is equal to 0 how you call that?@waterineyes
Which grade you are in @nia_maepenix
@waterineyes first year
Ah it's easy just it's all 0
If numerator is 0 then the value is 0 and not, not defined..
Have you studied about functions range domain etc..??
\[\large \frac{0}{1} = 0\] \[\large \frac{1}{0} = \color{green}{Undefined}\]
\[o \div x+3\]
So, you are allowed to make numerator 0 but denominator should be not equal to 0..
so any number divided by zero is equal to zero?
\[\large \frac{0}{x+3} = 0\]
If x is different than -3, so the value will be 0, if x= -3 it's undefined
0 is divided by any number is 0 @nia_maepenix
@waterineyes thanks a lot. I understand it now Dear
Here you are dividing 0 with x + 3 so : 0 divided by any number is 0 and any number divided by 0 is undefined..
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