Use the substitution method to solve the following system of equations.

4x – y – 3z = –3
x – 2y – 2z = –3
x + y + 3z = –2

(–1, 2, –1)

(1, –2, 1)

(–1, –2, 1)

(1, –2, –1)

Question

Use the substitution method to solve the following system of equations. 

4x – y – 3z = –3 
x – 2y – 2z = –3 
x + y + 3z = –2

 (–1, 2, –1)

 (1, –2, 1)

 (–1, –2, 1)

 (1, –2, –1)

anonymous · Answer

ok subtract equation 3 from 2 
x-2y-2z-(x+y+3z)=-3-(-2)
-3y-5z=-1 ...........A

multiply the equation 2 by 2 
4x-4y-8z=-6
subtract this from equation 1
4x-y-3z-(4x-4y-8z)=-3-(-6)
3y+5y=3    ..............B
solve equations A and B

anonymous · Answer

@priscillaam_0422  can you solve A and B equations ?

anonymous · Answer

yes! thank you somuch!

anonymous · Answer

and there is a typo the Equation B is 
3y+5z=3    ..............B

anonymous · Answer

yw:)