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Mathematics 12 Online
OpenStudy (anonymous):

simplify this (image attached)

OpenStudy (anonymous):

OpenStudy (anonymous):

how do i get the 125 down?

OpenStudy (lgbasallote):

well \[\huge 125 = 5^3\] does that help?

OpenStudy (anonymous):

do i use that with the 6?

OpenStudy (lgbasallote):

yes

OpenStudy (lgbasallote):

actually...it depends on what you meant...

OpenStudy (anonymous):

im a bit lost

OpenStudy (cwrw238):

(5^3)^(1/6) = 5 ^(3/6) = 5^(1/2) and (a^15)^(1/6) = ?

OpenStudy (cwrw238):

recall that 6th root = ^ (1/6)

OpenStudy (anonymous):

so a^5/2 ?

OpenStudy (cwrw238):

yes

OpenStudy (lgbasallote):

dont forget to simplify the whole thing

OpenStudy (anonymous):

how do i simplify 5^1/2 a^5/2

OpenStudy (anonymous):

@lgbasallote

OpenStudy (lgbasallote):

\[\huge x^{1/2} \times y^{1/2} \implies (xy)^{1/2} \implies \sqrt{xy}\]

OpenStudy (anonymous):

so i should put a square root over the five? err...

OpenStudy (anonymous):

or is it liike 5a^?/2

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