Question

convert the polar equation to rectangular form.
r=6/(2-3sin theta)

Answer 1

Can anyone help?

Answer 2

ok
in order to convert
use the following
\[\Large x^2+y^2=r^2\]
and
\[\Large y=rsin(\theta)\]

Answer 3

can you do this?

Answer 4

Sort of.

Answer 5

ok
replace sin(theta)=y/r
so
\[\Large (\sqrt{x^2+y^2})=\frac{6}{2-3y/r}\]

Answer 6

use again
\[\Large r=\sqrt{x^2+y^2}\]

Answer 7

is it ok now ?

Answer 8

Yes thank you

Answer 9

yw:)