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Mathematics 18 Online
OpenStudy (anonymous):

A library shelf has 6 identical mathematics books, 3 identical physics books and 4 identical chemistry books. The number of different possible arrangements of these books are

OpenStudy (ganpat):

maths book can be arranged in 6 different ways, so 6 ! physics book can be arranged in 3 different ways, so 3 ! chemistry book can be arranged in 4 different ways, so 4 ! So answer would be 6! * 3! * 4!...

OpenStudy (anonymous):

hm i got 103680 for that.. answer should be 60 060 i think

OpenStudy (ganpat):

@waterineyes , @ganeshie8 ???

OpenStudy (anonymous):

its okay i got it.. \[\frac{13!}{6!*4!*3!}\]

OpenStudy (anonymous):

They are identical this will make the difference I guess..

OpenStudy (anonymous):

Yes you are right @powerangers69 Well Done..

OpenStudy (ganpat):

hmmm, yes.. this is what we do for identical cases.. @powerangers69 : great job :)

OpenStudy (anonymous):

@Ganpat it is same as I had given you that day.. Remember taking example of your name??

OpenStudy (ganpat):

yup.. special case :)... thats y i called u over here :D...

OpenStudy (anonymous):

for probability how do u know when to times or to add ?

OpenStudy (ganpat):

if they say and than u shd multiply If they say or , that you should add...

OpenStudy (ganpat):

for eg: A bag has different color balls.. 1. pick the ball from the such that it is bag red and blue.. Multiply 2. Pick the ball from the bag it either red or blue.. add..

OpenStudy (anonymous):

a team of 3 boys and 3 girls is to be chosen from a group of 8 boys and 5 girls. How many idfferent teams are possible? 8C3 + or x 5C3

OpenStudy (ganpat):

8C3 x 5C3 as the question says, from a group of 8 boys AND 5 girls..

OpenStudy (ganpat):

and best example for the other operation (+ ) A team of 6 is to be chosen from a group of 8 boys and 5 girls. Such that at least 4 girls are included How many idfferent teams are possible? (8C2 x 5C4 ) + (8C1 x 5C5)... getting it ??

OpenStudy (anonymous):

yeahh around 85% understand :) adding the number of teams with at least 4 girls

OpenStudy (ganpat):

ha ha.. so what stuck up in 15 % ??

OpenStudy (anonymous):

is the answer to that queestion \[13C6 - (8C4*5C2)\] umm so in terms of tree diagram.. adding is like adding the number of branches on the same level while multiple is when u move along a branch

OpenStudy (ganpat):

answer to which question ??

OpenStudy (anonymous):

your example

OpenStudy (anonymous):

1-4boys = atleast 4 girls?

OpenStudy (ganpat):

what i mentioned over there is the answer.. (8C2 x 5C4 ) + (8C1 x 5C5)...

OpenStudy (ganpat):

like ,atleast 4 guls get selected 1. 4 girls selected= (8C2 x 5C4 ) 2. 5 girls r selected = (8C1 x 5C5)... there r only 5 girls.. if it would have been more..than it would have continued.. till the point all the girls r selected or the complete team is formed...

OpenStudy (anonymous):

yeah i get what you did just wondering if you can do using complement

OpenStudy (ganpat):

complement ??

OpenStudy (anonymous):

nevermind its okay.. another question The letters of the words ‘MATHS IS EASY’ are to be arranged in a row. The number of ways this can be done if the consonants are to be together i

OpenStudy (anonymous):

omg i did vowels.. let me try again

OpenStudy (ganpat):

|dw:1343649812152:dw| there are ll letters, excluding the spaces.. Now, A is occurring 2 times and s is occurring 3 times.. so have to divide by 2! * 3!.. also, Consonants should be together... consonants can be arrange in 7 ways so, 7! and remaining can be arranged in 5 ways.. 5 ! So i guess, (7! * 5! ) / (2! * 3!)...

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