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solving a system of equations solve 4x + 3y = 13 x + 5y = 33
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eliminate y first
1. multiply -4 to the 2nd equation -4(x+5y=33) implies -4x-20y=-132 2. add the 1st equation with the equation from the equation derive in 1 and solve for y. 4x+3y=13 + -4x-20y=-132 = -17y=-119 implies y=119/17=7 3. substitute y in any of the 2 equation and solve for x. x+5(7)=33 x=33-35=-2
-20x-15y=-65 3x+15y=99
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-17x=34 x=-2
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then substitute in your original equation to get y
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