4x^4-8x^3+3x^2

Question

4x^4-8x^3+3x^2

lgbasallote · Answer

factor out?

anonymous · Answer

$$4x ^{4} - 8x ^{3} +3x ^{2} = 0$$
try moving 3x^2 to the other side

anonymous · Answer

factor by grouping

anonymous · Answer

i dnt understand how to do it

cunningham2000 · Answer

Simpler than that.  Factor out an X squared  X^2 (4X^2 - 8x +3)  If you're supposed to factor it further you have to use quadratic equation for the part in parenthesis.  But this is usually the final answer since it's not an equation and can't be factored with integers.

cunningham2000 · Answer

I lied.  It can be factored further.  4x squared - 8x + 3 factors to (2x-1)(2x-3)

cunningham2000 · Answer

The way you factor at this point is you multiply the coefficient of x^2 times the constant and figure out what factors of 12 (in this case) will give you negative 8.  (4x-6) and (4x-2)  the negative 6 and negative 2 equal 8.  The 4x is repeated temporarily until you figure out that (4x-6) can be factored by 2 leaving (2x-3) and (4x-2) can be factored by 2 leaving (2x-1).  It's a little complicated when you have a lead coefficient.

cunningham2000 · Answer

Your final answer is  (x)(x)(2x-3)(2x-1)

hero · Answer

4x^4-8x^3+3x^2
4x^4-2x^3-6x^3+3x^2
2x^3(2x-1)-3x^2(2x-1)
(2x-1)(2x^3-3x^2)
(2x-1)(x^2(2x-3))
x^2(2x-3)(2x-1)

hero · Answer

That's the correct way to factor by grouping