Question

(x^2 y^-3)/3y^2 times (y^2)/x^-4

Answer 1

brb afk gotta eat dinner. just leave the steps and ans ry I will be back.

Answer 2

\[\frac{x^2y^{-3}}{3y^2} \times \frac{y^2}{x^{-4}} \implies \frac{x^2}{3y^5} \times \frac{y^2x^4}{1}\]I just used one fo the laws of exponents:
\[a^{-b} = \frac{1}{a^b}\]Can you finish it up?

Answer 3

ummmm

Answer 4

Hint: Cross cancel

Answer 5

where did you get b from?

Answer 6

nice hint/answer LOLZ

Answer 7

lol It's just a random variable...it demonstrates the one of the law of exponents.

Answer 8

Do you get it???????????????????¿???????????????????¿???????????????????¿???????????????????¿

Answer 9

yah

Answer 10

Alright. What is the final answer then?

Answer 11

x^6/3y^3

Answer 12

How in the world did I miss this? You are correct XD