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Mathematics 30 Online
OpenStudy (anonymous):

A carton contains 4 black tiles, 5 white tiles, and 3 brown tiles. If tiles are drawn at random without replacement, what is the maximum number of tiles that could be drawn without picking two of the same color? (a) 3 (b) 4 (c) 5 (d) 6 (e) 8

OpenStudy (nottim):

Statistics rite? What have you done/ what do oyu know about this?

OpenStudy (anonymous):

yeah i don't know much about statistics. this is one of my sat questions.

OpenStudy (nottim):

oooh

OpenStudy (nottim):

well....do you kno about 5! ?

OpenStudy (nottim):

actuallly...i forogt statistics tooo..whoops

OpenStudy (anonymous):

yeah that's = to 5 x 4 x 3 x 2x 1

OpenStudy (nottim):

eh...what about nPr (pick) and nCr (choose)?

OpenStudy (anonymous):

i'm not sure

OpenStudy (nottim):

eh...look that up?

OpenStudy (nottim):

...i dont seem to be of much help...

OpenStudy (nottim):

so...

OpenStudy (anonymous):

it's ok

OpenStudy (nottim):

sorry broski. ask me a few years early and I'd be able to answer this one.

OpenStudy (nottim):

i've even lost my notes for this subject...

OpenStudy (anonymous):

that's fine i found the answer online. its choice (a) 3 but i still don't know how

OpenStudy (anonymous):

oh wait i get it. it's actually very simple. since there's three different types of colors then obviously you can pick a max of 3 to still get a different color each time

OpenStudy (nottim):

whoa...i overlooked the simple stuff. smart thinkin

OpenStudy (nottim):

WAIT

OpenStudy (nottim):

Jsut 2, not 3...

OpenStudy (nottim):

"...drawn without picking two of the same color?"

OpenStudy (nottim):

two...

OpenStudy (nottim):

so...

OpenStudy (anonymous):

but that's not even an answer choice

OpenStudy (nottim):

no, the answer IS NOT 2, that's not what I meant lol

OpenStudy (nottim):

you know what, I don't think I'm much help. I think you got your answer right (of 3). Don't quote me tho...

OpenStudy (nottim):

imma go...if you need help, call out. if you wanna contact smarter people, use @therename

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