Question

Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.

4x + 4y = 6

x + 4y = 12

4x + 4y = –12

x – 4y = –6

Answer 1

use the two point formula \[\large y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x - x_1)\]
\[\implies y - 2 = \frac{3 - 2}{6-2} (x - 2)\]
\[\implies y- 2 = \frac 14 (x-2)\]
multiply all terms by 4
\[\implies 4y - 8 = x - 2\]
put everything to the left side
\[\implies 4y - 8 - x + 2 = 0\]
\[\implies 4y - x - 6 = 0\]
does that help?

Answer 2

btw if you think i just gave you an answer weely-neely you're wrong...you have to manipulate that thing i gave so it'll look something like one of your choices ;)