solve the linear system using the addition-elimination method
3x-5y=-2
-2x+4y=1
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OpenStudy (cwrw238):
multiply the first equation by 2 and second one by 3
adding these 2 new equations will eliminate x
then solve for y
finally find x by plugging value of y into first equation
OpenStudy (anonymous):
i cant figure out the values, every time i try i get different numbers that dont work in the equation
OpenStudy (cwrw238):
ok ill start it for you
6x - 10y = -4 thats first equation x 2 - remember to multiply each term by 2
now second by 3:-
-6x + 12y = 3
adding 2y = - 1
OpenStudy (cwrw238):
do u follow that?
OpenStudy (anonymous):
yeah i get that its just when i try to find x and plug both numbers back to check if its right it doesnt work out
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OpenStudy (cwrw238):
y = 1/2 right?
OpenStudy (anonymous):
i got y= -1/2
OpenStudy (anonymous):
and x = 1 1/2 which doesnt work in the equation
OpenStudy (cwrw238):
good - u spotted my deliberate mistake
now you plug y = -1/2 into
3x - 5y = -2
OpenStudy (cwrw238):
3x - 5(-1/2) = -2
3x = -2 - 5/ 2
right?
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OpenStudy (anonymous):
its 3x = -4 1/2
and x = (-4 1/2)/3
OpenStudy (cwrw238):
3x = -9/2
x = -9/2 * 1/3 = -9/6 = -3/2
OpenStudy (cwrw238):
yea
OpenStudy (cwrw238):
-3/2 = -1 1/2
OpenStudy (anonymous):
right, but when i plug that in it doesnt work. it comes to -3.5 + 2.5 = -2
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OpenStudy (anonymous):
oh i just realized what i did wrong. thank for your help :-)