Question

Construct a truth table for ~q --> (p V q) Be sure to include all intermediate steps in your table.

Answer 1

is that:
NOTq Implies (p OR q)

Answer 2

if so:
p=0
q=0
NOT 0 = 1
0 OR 0 = 0
1-> 0 = 0

Answer 3

p = 1
q = 0
NOT 0 = 1
1 OR 0 = 1
1 -> 1 = 1

Answer 4

p = 0
q = 1

NOT 1 = 0
0 OR 1 = 1
0 -> 1 = 1

Answer 5

p = 1
q = 1
NOT 1 = 0
1 OR 1 = 1
0 -> 1 = 1

Answer 6

so:

p q 0utput
0 0 0
1 0 1
0 1 1
1 1 1

Answer 7

You kind of confused me with what you was saying And we use T and F. Could you be a ittle more clearer please on the answer.

Answer 8

well, 0 is F, and 1 is T

Answer 9

so:
p=F
q=F
NOT F = T
F OR F = F
T-> F = F

Answer 10

I just plugged the inputs into the equation step-by-step

Answer 11

starting with the first part, NOT q

Answer 12

then p OR q

Answer 13

finally I plugged those results into the Implies operator

Answer 14

so first I said NOT q = a
then I said p OR q = b
then I said a -> b = output

Answer 15

So basically, the very last symbol of my responses are the answers