I need step by step instruction on this precal/trig problem to get an answer :/ Please help? Click on attached
So we're in quadrant 3. Which one is that. What is 2/5 in decimal and which angle has that as its cosine?
Q3 is the lower left. 2/5 in decimal form is 0.4?
angle?
Not sure :/
Hang on, but you should have a function like that on your calculator.
I found one online http://www.rapidtables.com/calc/math/Arccos_Calculator.htm 66.4 degrees Sounds about right
So the angle with cosine 0.4 is 66.4 degrees. If we sketch that in the first quadrant you'll see that an x value of 2 and a radius of 5 looks about right. OK?
Yes, sounds right.
Now what we need to do is to rotate that guy into the third quadrant. The angle will be 180 degrees plus 66.4. Notice that since x < 0, cosine is now negative, as given in the problem.
Oh, yea, I understand
A = 180 + 66.4 = 246.4 A/2 = 123.2 cos (A/2) = ?
Hmm... -0.547?
Yep. A/2 is in quadrant 2, so cosine is negative.
So how would the final result look like? I'm sorry, I usually have multiple choice to choose from
Usually for something like this you would show your work, I'd put the steps we went through and why, and diagrams and everything. But the answer is just this number that we calculated. How do you enter your answers??
Oh o.k, simple enough. Thank you so much for your help, I really appreciate it!
yw
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