Question

What are the zeros of the function f(x) =3x^2-3x-6/3x-6

Answer 1

you mean f(0)?

Answer 2

no f(x)

Answer 3

the zeroes would be simply when f(x) = 0 then solve for the value of x

Answer 4

\[\frac{3x^2 - 3x-6}{3x - 6} = 0\]
solve for x

Answer 5

does that help? or do you need more help?

Answer 6

i need more help idont know how to solve that

Answer 7

start by factoring out the numerator and denominator. what do you get?

Answer 8

3x^2=0 right

Answer 9

no

Answer 10

you cannot cancel 3x-6 that easily

Answer 11

you factor it this way \[\frac{3(x^2 - x - 6)}{3(x-2)} = 0\]
got it?

Answer 12

uhh wait that should be 2

Answer 13

\[\frac{3(x^2 - x - 2)}{3(x-2)} = 0\]

Answer 14

now what can you cancel?

Answer 15

x-2 and 3

Answer 16

you cant cancel x-2

Answer 17

when you have addition you cant cancel

Answer 18

when you have x^2 - x - 2 and x - 2 you cant cancel x-2

Answer 19

because there is x^2

Answer 20

so 3 is the only thing that you can cancel \[\frac{x^2 - x - 2}{x-2} = 0\]
now factor out the numerator

Answer 21

idk im just trying to pass the class this is my last lesson so ill go with -1

Answer 22

just factor out the numerator

Answer 23

what is the factored form of x^2 - x -2

Answer 24

you know how to factor right?