Question

Algebra....Soving Equations with Radicals

The square root of 3x +10 = 2x-5 ???

Answer 1

\[ \large \sqrt{3x+10}=2x-5 \]
??

Answer 2

correct

Answer 3

Edwin???

Answer 4

square each side of the equation

Answer 5

\[3x+10=4x ^{2}-20x+25\]

Answer 6

yes
now it is a quadratic equation
can u solve this?

Answer 7

No...

Answer 8

I'm stuck at this point

Answer 9

put everything on one side
\[ \large 0=4x^2-20x+25-3x-10=4x^2-23x+15 \]

Answer 10

where did the 25 come from?

Answer 11

now
\[ \large 0=4x^2-23x+15=\frac{(4x-20)(4x-3)}{4} \]
\[ \large =\frac{4(x-5)(4x-3)}{4}=(x-5)(4x-3) \]

Answer 12

u posted it

Answer 13

oh. O.K.

Answer 14

x=5, x=3/4 ???

Answer 15

yes

Answer 16

did u understand it?

Answer 17

yes....Thanks Edwin....!!!

Answer 18

u r welcome
my name is Helder (Edwin is my middle name)