Question

PLLLEEZZZ! solve: 7^(x-5)=7^(4x+7)

Answer 1

take log of base 7 on both sides to get x-5 = 4x + 7

Answer 2

\[\large x^a = x^b \implies a = b\]

Answer 3

No need to take log here..

Answer 4

Just equate the exponents...

Answer 5

i dont understand...

Answer 6

since bases are same so just equate both sides
\[\Large (x-5)=4x+7\]
take all the x terms to one side
\[\Large 4x-x=-12\]
\[\Large 3x=-12\]
i hope you got it.

Answer 7

Tell me what are the exponents both the sides ??

Answer 8

@cassie4math did you get it?

Answer 9

I give you the example:

\[\huge 5^{x-6} = 5^{-2x}\]

This implies :

\[\large x - 6 = -2x\]

Answer 10

so x=-4 riught?

Answer 11

Well Done..

Answer 12

thanks!

Answer 13

Welcome dear..