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Help please for equation that represents the line that passes through the point (-2, 6) and has a slope of 4?
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Start with y = mx+b where m is the slope and b is the y-intercept
You're given a slope of 4. So m = 4 One point that lies on the line is (-2,6). So x = -2 and y = 6 So y = mx+b becomes 6 = (4)(-2)+b Now solve for b
How do I do that....
6 = (4)(-2)+b will become 6 = -8+b what's next?
@jim_thompson5910 do I subtract 8?
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6 = -8+b is the same as 6 = b-8 so what's next?
divide?
add 8 to both sides
so 14 = b :D
yes, which means that y = mx+b becomes y = 4x+14
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since m = 4 and b = 14
Oh okay thanks
yw
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