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Mathematics 15 Online
OpenStudy (anonymous):

what is the sum of the angle measures in a pentagon?

OpenStudy (amistre64):

which angles?

OpenStudy (anonymous):

thats all the question says thats why i am confused!!!

Parth (parthkohli):

Maybe that means the interior angles.

OpenStudy (amistre64):

it prolly wants the interior angles formed at the vertexes

Parth (parthkohli):

The sum of interior angles in an n-sided polygon is \(180(n - 2)\).

OpenStudy (anonymous):

Probably...

Parth (parthkohli):

And, the sum of exterior in ALL polygons is 360 degrees.

Parth (parthkohli):

exterior angles*

OpenStudy (amistre64):

|dw:1343837286282:dw|

Parth (parthkohli):

A pentagon has 5 sides, so you must replace 5 with n to find the sum of interior angles.

Parth (parthkohli):

@Jodi103 Can we please have a response from you here?

OpenStudy (amistre64):

we get isocolese triangles; with a central angle of 360/5 for a pentagon or 72 degrees, the base angles are then 180-72 = 108 each

OpenStudy (amistre64):

since there are 5 pointy parts that measure 108 each 5*108 should do it

Parth (parthkohli):

@amistre64 108 degree interior angle only in the case of a regular pentagon. ;)

OpenStudy (anonymous):

okay thank you I understand. I appreciate the help from all of you guys :D

OpenStudy (amistre64):

i only work with regular pentagons, all others i throw in the trash ;)

Parth (parthkohli):

But yes, the sum still remains 108 * 5 :)

OpenStudy (anonymous):

Okay thanks;)

Parth (parthkohli):

You're welcome!

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