what is the sum of the angle measures in a pentagon?
which angles?
thats all the question says thats why i am confused!!!
Maybe that means the interior angles.
it prolly wants the interior angles formed at the vertexes
The sum of interior angles in an n-sided polygon is \(180(n - 2)\).
Probably...
And, the sum of exterior in ALL polygons is 360 degrees.
exterior angles*
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A pentagon has 5 sides, so you must replace 5 with n to find the sum of interior angles.
@Jodi103 Can we please have a response from you here?
we get isocolese triangles; with a central angle of 360/5 for a pentagon or 72 degrees, the base angles are then 180-72 = 108 each
since there are 5 pointy parts that measure 108 each 5*108 should do it
@amistre64 108 degree interior angle only in the case of a regular pentagon. ;)
okay thank you I understand. I appreciate the help from all of you guys :D
i only work with regular pentagons, all others i throw in the trash ;)
But yes, the sum still remains 108 * 5 :)
Okay thanks;)
You're welcome!
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